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Hey Richard,
What i meant is methanol to fuel ratio, since I already stated that I'll be running 100% meth.
Plz tell me if the below is true:
Let's say I want to run 30/70 MFR. Alky's are like 30% lighter than fuel from what I read here, accordingly a 30/70 combination by mass would require 43% cc's of meth (43% of the total fuel cc's).
ie: using stock injectors, 4x560 = 2240 cc's
meth required to run 30/70 MFR: 2240x43% = 963 cc nozzle (w'out taking account of the manifold pressure reducing the meth pump flow)
Now if i want to run 50/50 MFR, why doesn't the above logic apply??
I hv no prob programming a microcontroller to generate my own PWM based on the RPM and boost in case this is required to run a 50/50 MFR, but I need to know the reason why I can't just mirror the injectors duty cycle for above 30/70 MFR.
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